Please show calculations on how to make a 0.125M NaOH solution using 30%m/v of N

Question

Please show calculations on how to make a 0.125M NaOH solution using 30%m/v of NaOH. Assume it's in a laboratory setting so flasks can be used.

30% m/v sodium hydroxide (molar mass-40.00 g/mol) Potassium hydrogen phthalate (KHP, molar mass 204.2 g/mol) Deoxygenated water Unknown acid sample Phenolphthalein (molar mass 318.3 g/mol, pKa 9.10) Laboratory glassware Burette and burette accessories pH probe and LoggerPro pH-pKa+ lo IAS (10 points) You begin by preparing 250.00mL of a~0.1250M solution of NaOH. In the space below, discuss how you will prepare this solution, using calculations to support your answer.

Explanation / Answer

30%m/v NaOH means 30g of NaOH dissolved in 100 mL of solution

molarity of this solution = (30 / 40 ) / 0.1 = 7.5 M

using M1V1 = M2V2

M1 = 7.5 M

V1=?

M2 = 0.125 M V2 = 250 mL

V1 = M2*V2 / M1 = 0.125*250 / 7.5 = 4.167 mL

so taking 4.167 mL of 30%m/v NaOH solution in flask and diluting it to 250 mL using water.

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