ing and learning resource from Cengage Learning Google Chrome n/takeAssignment/t

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ing and learning resource from Cengage Learning Google Chrome n/takeAssignment/takeCovalentActivity.do?locator assignment-take&takeAssignmentSessionLocator-assignment-ta; Use the Referesces to access isportast ralues if seeded foe this qaestion A sample of gas contains 0.1900 mol of CH() and 0.3800 mol of O() and occupies a volume of 22.9 L The following reaction takes place Cakulate the volume of the sample ater the reaction takes place, assum that the temperature and the pressureem.an Submit Answr Retry Entire Group 6 more group attempts

Explanation / Answer

From the stoichiometry of the reaction

Stoichiometric Molar ratio of CH4 : O2 = 1 : 2

From the given data

Molar ratio of CH4 : O2 = 0.1900 : 0.3800 = 1 : 2

Before the reaction

Total Moles n1 = 0.1900 + 0.3800 = 0.5700 mol

Volume V1 = 22.9 L

After the reaction

Moles of CO2 formed = moles of CH4 consumed = 0.1900 mol

Moles of H2O formed = 2*0.1900 = 0.3800 mol

Total Moles n2 = 0.1900 + 0.3800 = 0.5700 mol

Volume V2 =?

At constant temperature and pressure

From the Avogadro's Law

V1/n1 = V2/n2

V2 = V1*n2/n1

= 22.9*0.5700/0.5700

= 22.9 L

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