inematics m 6 60127 : A toy rocket is launched vertically from ground level (y 0

Question

inematics m 6 60127 : A toy rocket is launched vertically from ground level (y 0.00 m), at time t0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 62 m and acquired a velocity of 10 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and talls back to the ground with negligible air resistance. The speed of the rocket upon impact on the ground is closest to 36 mis 30 mis 41 mis 33 mis 44 mis

Explanation / Answer

First option '36 m/s' is the correct answer.

Explanation -

At the instant the rocket engine burnt out, the velocity of the rocket, u = 10 m/s

Suppose from this point the rocket rises a height of 'h' meter.

Determine this height.

Use the expression -

v^2 = u^2 + 2*a*h

At the maximum height, v = 0

so we have -

0 = 10^2 - 2*g*h

=> h = 10^2 / (2*g) = 100 / (2*9.8) = 5.10 m

So, total height reached by the rocket, H = 62 + 5.10 = 67.10 m

So, velocity of the rocket when it fall from a height H = sqrt(2*g*H) = sqrt(2*9.8*67.10) = 36.3 m/s

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