A solution is composed of 1.90 mol cyclohexane (P degreeree cy = 9.76 torr) and

Question

A solution is composed of 1.90 mol cyclohexane (P degreeree cy = 9.76 torr) and 2.50 mol acetone(P degreeree ac = 229.5 torr). What is the total vapor pressure Ptotal above this solution? Express vour answer with the appropriate units. If a third volatile component had been present in this solution, the total pressure would be calculated in a similar manner but would involve three terms rather than two. For example Ptotal = PA + PB + PC = XP degreeree A + XP degreeree B + XP degreeree C As you saw in Part B. the vapor above the cyclohexane-acetone solution is composed of both cyclohexane vapor and acetone vapor. What mole fraction of the vapor above the solution, Xcy(vapor), is cyclohexane? Express your answer numerically. Xcy(vapor) =

Explanation / Answer

Pa=PoaXa where Xa is the mole fraction of A int the solution, Pb=Pob Xb where Xb is the mole fraction of B in the solution, so mole fraction of A in vapour = PoaXa/(PoaXa + Pob Xb) =42.14/(130.39+42.14) =0.244 please appreciate me by awarding me karma points.

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