A solution contains 15 g of CaCl_2 in a total volume of 190 mL. Express the conc

Question

A solution contains 15 g of CaCl_2 in a total volume of 190 mL. Express the concentration in terms of grams/liter, % w/v, molars, and millimolars. Given stock solutions of glucose (1 M), asparagine (100 mM) and NaH_2PO_4 (50 mM), how much of each solution do you need to prepare 500 mL of a reagent that contains 0.05 M glucose, 10 mM asparagine, and 2 mM NaH_2PO_4? Calculate the number of millimoles in 500 mg of each of the following amino acids: alanine (MW = 131), tryptophan (MW = 204), cysteine (MW = 121), and glutamic acid (MW = 147). What molarity of HCl is needed so that 5 mL diluted to 300 mL will yield 0.2 M?

Explanation / Answer

5.

1.

grams / liter = mass of solute in g / volume of solvent in L

Here ; mass of solute = 15 g and volume of solvent =190 m L= 0.190 L

Concentration in grams / liter = 15 g/ 0.190 L

= 78.95 g/ L

2

% w/v= mass of solute in g / volume of solvent in mL *100

= 15 g / 190 ml*100

= 7.895 % w/v

3

Number of moles = amount in g / molar mass

= 15 g / 110.98 g/mol

= 0.135 moles

Molarity = number of moles / volume in L

Volume = 190 ml = 0.190L

Molarity = 0.135 moles /0.190 L

= 0.71M

4

1 .0 M= 1000 milli-moles

0.71 moles / L*1000 milli-moles

= 710 mm/L

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