A reaction has a standard free-energy change of 4 90 kj/mol at 25 degree C, What

Question

A reaction has a standard free-energy change of 4 90 kj/mol at 25 degree C, What are the concentration of A, B and C at equilibrium if, at the beginning of the reaction, their concentration are 0.30 M 0.40 M. and 0 M, respectively? How would your answers above change if the reaction had a standard free-energy change of +4.90 kJ/moJ? There would be no change to the answers. There would be more A and B but less C. There would be less A and B but more C All concentrations would be higher All concentrations would be lower

Explanation / Answer

dG = - 3.10 & a later sentence has it as dG = + 3.10 calc K, if dG = + 3.10 dG = -RT lnK 3.10 kJ = - ((.008314) (298Kelvin) lnK lnK = - 0.4036 e^x K = 0.668 under this situation, the products are not favored... but since the term "equilibrium" indicates that it wi;; proceed to set up some ratio... the concentrations of A & B will decrease while the concentration of C will increase ================ under the situation where dG = - 3.10 the product "C" is favored & even more will ... the concentrations of A & B will decrease while the concentration of C will increase

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.