The figure below is a heat curve for an unknown outerspace substance discovered

Question

The figure below is a heat curve for an unknown outerspace substance discovered by the Mars rover. By understanding the heat curve, scientists can make inferences about the composition of the planet What is the temperature of fusion, Tfusion, and vaporization, Tvapor, for this unknown substance? Note that the units are graded Temperature (C) 400 380 360 340 320 300 280 260 240 220 200 180 160 140 120 100 80 60 Number Units fusion Number Units vapor For a sample of 70.6 g of this substance with a specific heat of 46.4 J/kg. °C, how much heat is added to the substance if the temperature is to change from 180.0°C to 238.0°C? 20 -60 -80 40 80 120 160 Number Time

Explanation / Answer

1) according to the graph given , T fusion is the temperature of phase change from solid to liquid , so the temperature remains constant at 80 degree C so at this temperature fusion takes place

2) 280 degree C is the vaporisation temperature as during the phase change the temperature remains constant ,

3) heat = mass x specific heat x temperature change =0.0706 x46.4 x (238 -- 180)= 190.8 J

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