The figure below gives the parameter beta of the equation shownbelow versus the

Question

The figure below gives the parameter beta of the equation shownbelow versus the sine of the angle theta in a two-slitinterference experiment using light of wavelength 440 nm. (The vertical axis is marked in increments of25 rad.) (a) What is the slit separation? mu m (b) Assume that none of the interference maxima are completelyeliminated by a diffraction minimum. What is the total number ofinterference maxima? (Count them on both sides of the center of theinterference pattern.) maxima (c) What is the smallest (non-negative) angle for a maximum? (d) What is the largest angle for a minimum?

Explanation / Answer

to get the right answer for part d use the equation d sin()=(m+1/2) d= slit separation in part a m=((63-1)/2 )-1 so your m will equal 30 = 440nm plugging in these values gives you a =73.44 degrees the reason to subtract the extra 1 off the end of your mvalue is that if you use m=31 you will find a minimum just beyondthe diffraction minimum and not the first one between the twodiffraction minimums which is what the problem is asking for.

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