The figure bellows shows two parallel plates. Assume they are infinite in area (
ID: 2001886 • Letter: T
Question
The figure bellows shows two parallel plates. Assume they are infinite in area (this way we can neglect edge effects). The plate on the left is at a potential of +56V and the plate on the right is at a potential of OV. The plates are a distance 28cm apart and the dashed lines are spaced equally 7cm apart. Evaluate the following statements appropriately: The electric potential energy of an electron at point A is_the electric potential energy of an electron at point B. The electric potential at point C is_the electric potential at point F. The electric potential energy of a proton at point A is_the electric potential energy of an proton at point C. The electric potential at point C is_the electric potential at point A. What is the electric potential at point A? What is the magnitude of the electric field at point C?Explanation / Answer
change in potential energy is U2-U1 = q*(V1-V2)
So the electric potential energy of an electron at point A is larger than the the electric potential energy of an electron at point B
the elctric potential at point C is equal to the electric potential at point F
the electric potential energy of an electron at point A is larger than the the electric potential energy of an electron at point C
the elctric potential at point C is less than the electric potential at point A
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Electric potential at A is VA
then (56-0)/28 = (56-VA)/7
VA = 42 V
electric potential at C is VC
(56-0)/28 = (56-VC)/21
56- VC = 42
VC = 56-42= 14 V
then Electric field at C is (VC-VA)/d = (42-14)/(0.14) = 200 N/C
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