A simple and common technique for accelerator electrons is shown in the figure,

Question

A simple and common technique for accelerator electrons is shown in the figure, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. Calculate the horizontal component of the acceleration of the electron if the field strength is 2.7 x 10^4 N/C. Express your answer m m/s^2, and assume the electric field is pointing in the negative x direaction as shown in the figure.

Explanation / Answer

F = ma

F= qE

a = qE/m

a = 1.6*10^-19 x 2.7 * 10^4 / ( 9.1 * 10^-31 )

a = 4.75 x 10^15 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.