A silver dollar is dropped from the top of a building that is 1343 feet tall. Us
ID: 1437987 • Letter: A
Question
A silver dollar is dropped from the top of a building that is 1343 feet tall. Use the position function below for free-falling objects.
s(t) = 16t2 + v0t + s0
(a) Determine the position and velocity functions for the coin.
(b) Determine the average velocity on the interval [2, 3].
3 ft/s
(c) Find the instantaneous velocities when t = 2 seconds and t = 3 seconds.
(d) Find the time required for the coin to reach the ground level. (Round your answer to three decimal places.)
t = 6 s
(e) Find the velocity of the coin at impact. (Round your answer to three decimal places.)
7 ft/s
Explanation / Answer
Given
s(t) = 16t2 + v0t + s0
a)
For free fall
s(t) = 16t2
v(t) = dS/dt = -32t
b)
at 2s
S1 = -64 ft and
at 3s S2 = -144 ft
average velocity
Vavg = S2 - S1 / t2 - t1
V = 80 ft/s
c)
at t = 2s
v(2) = 32 * 2 = 64 ft/s
V(3) 32 * 3 = 96 ft/s
d)
in free fall t
total time t = sqrt( 1343/16)
t = 9.16 s
e)
v = sqrt (2 * g * h)
v = 291.46 ft/s
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