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Youbook xWileyPLUS e Chegg Study | Guide WebAssign -> C D edugen.wileyplus.com/edugen/student/mainfr.un. WileyPLUS Halliday, Fundamentals of phiysics Extended, Be Halliday, Fundamentals of Physics Extended, 8e Capture Introductory Physics with Calculus (PHY203-204) Home Read, Study & Practice Assignment Gradebook AssignmentOpen Assignment MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 30, Problem 48 PHY204 Inductors in parallel. Two inductors L1-1.33 H and L2-2.05 H are connected in parallel and separated by a large distance so that the magnetic field of one cannot affect the other. (a) Calculate the equivalent inductance. (Hint: Review the derivations for resistors in parallel Chapter 3.21 H 1n parallel? and capacitors in parallel·Which is similar here?) (b) What is the generalization of (a) for N = 13 similar inductors L (a) Number (b) Number Answer a1: the tolerance is +/-5% hapter 104 SN Chapter 29, Probl PHY204 16-Pool5 Units Units Review Sco Answer b1: the tolerance is +/-5% Click if you would like to Show Work for this question: Sho SHOW HINT LINK TO TEXT Link to Sample Problem Link to Sample Problem Question Attempts: 0 of 5 used SAVE FOR LATER SUBMIT ANSWER Copyright © 2000-2016 by John Wiley & Sons, Inc. or related companies. All rights reserved License AgreementPrivacy Policy 2000-2016 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc Version 4.17.2.2

Explanation / Answer

Part A

Equivalent inductance in parallel

1/Leq = 1/L1 +1/L2

Leq = L1 * L2/(L1+L2)

Leq =1.33*2.05 /(1.33+2.05)

Leq = 0.80H

Part b

for N = 13 inductors

1/Leq = N/L

Leq = L/N =L/13

Leq = 3.21/13

Leq = 0.24H

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