4. Calculale the number of aoos in the fol greatest number of atoms? 1 mol-622 x

Question

4. Calculale the number of aoos in the fol greatest number of atoms? 1 mol-622 x 1O samples. Which sample contains the atoms a 100 g Pb b. 100 g Fe c. 100g Xe d 10.0g H e. 100 g Fr compound has a molar mass of 180.1 gimol and has the following composition by mass: C-400%; H-6.70%;0-53-y% Desemnine the empirical formula, the empirical Somula molar mass, and the molecular formala of the compound 6 A 5. Calculate the mass in amu for the following number of atoms a 250 atoens of H Se b. 13 atoems of UF c. 5000 atoms of P,Os d. 85 atoms of LiAs e. 99 atoms of KCrO f. 6 atoms of MgCIOh

Explanation / Answer

4) a)   mass = 10g                1 mol = 6.02214179×1023 atoms

lead (pb) atomic mass = 207 g

So, moles = mass/atomic mass = 10/207 = 0.0483 M

no. of atom = 0.0483 * 6.02214179×1023 = 0.29 * 1023

b)   mass = 10g                1 mol = 6.02214179×1023 atoms

iron (Fe) atomic mass = 56 g

So, moles = mass/atomic mass = 10/56 = 0.178 M

no. of atom = 0.178 * 6.02214179×1023 = 1.075 * 1023

C)    mass = 10g                1 mol = 6.02214179×1023 atoms

Xenon(Xe) atomic mass = 131 g

So, moles = mass/atomic mass = 10/131 = 0.0763 M

no. of atom = 0.0763 * 6.02214179×1023 = 0.459 * 1023

D)   mass = 10g                1 mol = 6.02214179×1023 atoms

Hafnium(Hf) atomic mass = 178 g

So, moles = mass/atomic mass = 10/178 = 0.056 M

no. of atom = 0.056 * 6.02214179×1023 = 0.338 * 1023

E) mass = 10g                1 mol = 6.02214179×1023 atoms

Francium(Fr) atomic mass = 223 g

So, moles = mass/atomic mass = 10/223 = 0.0448 M

no. of atom = 0.0448 * 6.02214179×1023 = 0.27 * 1023

So, Iron has highest number of atoms.

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