Map The equilibrium constant, K, of a certain first order reaction was measured

Question

Map The equilibrium constant, K, of a certain first order reaction was measured at two temperatures, T. If you were going to graphically determine the enthalpy, AH°, for this reaction, what points would you plot? The data is shown in this table Number Number T(K)K 325 875 To avoid rounding errors, use three significant figures in the x values and four significant figures in the y values point 1: 3.35 7.68 Number Number point 2 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the standard enthalpy of this reaction? Number J/ mol

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis
K = 3.35
ln K = ln (3.35) = 1.20896
T = 325.0
1/T = 0.00308


point 1 is:
x = 0.00308
y = 1.20896


K = 7.68
ln K = ln (7.68) = 2.03862
T = 875.0
1/T = 0.00114


point 2 is:
x = 0.00114
y = 2.03862


----------------------------------------------------------------------------
rise = (y1-y2) = 1.20896 - 2.03862 = -0.82966
rise = (X1-X2) = 0.00308 - 0.00114 = 0.00193
slope = rise/run
= -0.82966/0.00193
= -428.97152
----------------------------------------------------------------------------
use
slope = - Hvap/R
= -428.97152 = -Hvap/8.314
Hvap = 3566 J/mol
Answer: 3566 J/mol

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