Map Sapling Learning macmillan learning If you were going to graphically determi

Question

Map Sapling Learning macmillan learning If you were going to graphically determine the activation energy of this reaction, what points would you plot? Consider this reaction data A products Number Number T (K) k(s) 225 625 point 1: To avoid rounding errors, use at least three significant fiqures in all values 0.388 0.892 Number Number point 2 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the activation energy of this reaction? Number J/ mol PreviousGive Up & View SolutionCheck Answer Next Exit

Explanation / Answer

We need to plot lnK on y axis and 1/T on x axis
K = 0.388
ln K = ln (0.388) = -0.94675
T = 225.0
1/T = 0.00444


point 1 is:
x = 0.00444
y = -0.94675


K = 0.892
ln K = ln (0.892) = -0.11429
T = 625.0
1/T = 0.0016


point 2 is:
x = 0.0016
y = -0.11429


----------------------------------------------------------------------------
rise = (y1-y2) = -0.94675 - -0.11429 = -0.83246
rise = (X1-X2) = 0.00444 - 0.0016 = 0.00284
slope = rise/run
= -0.83246/0.00284
= -292.662
----------------------------------------------------------------------------
use
slope = - Ea/R
= -292.662 = -Ea/8.314
Ea = 2433 J/mol
Answer: 2433 J/mol

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