A voltaic cell contains two half-cells. One half-cell contains a chromium electr

Question

A voltaic cell contains two half-cells. One half-cell contains a chromium electrode immersed in a 1.00 M Cr(NO3)3 solution. The second half-cell contains a copper electrode immersed in a 1.00 M Cu(NO3)2 solution Cr (aq) 3eCr(s) E red-0.744 V Cu2+(aq) + 2 e- Cu(s) E red = +0.342 V (a) Using the standard reduction potentials given above, predict the standard cell potential of the voltaic cel (b) Write the overall balanced equation for the voltaic cell. (Include states-of-matter under the given conditions in your answer.) chemPad Help Greek

Explanation / Answer

a)

the one with greater Eo value will be reduced and will act as cathode

Eo cell = Eo cathode - Eo anode

= 0.342 - (-0.744)

= 1.086 V

Answer: 1.086 V

b)

reduction half cell is:

Cu2+(aq) + 2e-   —> Cu (s)

oxidation half cell is:

Cr (s) —> Cr3+ (aq) + 3 e-

Overall balanced equation will be:

3 Cu2+(aq) + 2 Cr (s) —> 3 Cu (s) + 2 Cr3+ (aq)

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