CHEMICAL Calculating the heat of reaction from molar reaction enthalpy and. A ch

Question

CHEMICAL Calculating the heat of reaction from molar reaction enthalpy and. A chemist measures the energy change H during the following reaction: 2Fe,03(s) 4 FeO(s)+02(g) AH=560. kJ Use the information to answer the following questions. endothermic exothermic ) Yes, absorbed. O Yes, released. This reaction is... Suppose 59.6 g of Fe,O react. Will any heat be released or absorbed? No. If you said heat will be released or absorbed in the second part of this question, calculate how much heat will be released or absorbed. Round your answer to 3 significant digits.

Explanation / Answer

1)

since H is positive, the reaction is endothermic

Answer: endothermic

2)

Reaction is endothermic

SO, heat is being absorbed

Answer:

yes, absorbed

3)

Molar mass of Fe2O3 = 2*MM(Fe) + 3*MM(O)

= 2*55.85 + 3*16.0

= 159.7 g/mol

mass of Fe2O3 = 59.6 g

we have below equation to be used:

number of mol of Fe2O3,

n = mass of Fe2O3/molar mass of Fe2O3

=(59.6 g)/(159.7 g/mol)

= 0.3732 mol

from reaction,

2 mol of Fe2O3, heat absorbed = 560 KJ

So,

heat absorbed = mol of Fe2O3 reacting * 560 / 2

heat absorbed = 0.3732 * 560 / 2 KJ

heat absorbed = 104 KJ

Answer: 104 KJ

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