to calibrate the calorimeter cup, first put 45 mL of cold water in a cup and mea
ID: 558014 • Letter: T
Question
to calibrate the calorimeter cup, first put 45 mL of cold water in a cup and measure its temperature to 21.7 Celsius. you then pour 59 mL of hot water (temperature 50.1 Celsius) into a cup and measure the temperature using the Vernier software for 10 minutes. after interpreting the cooling curve below the final temperature after mixing is 39.4 Celsius.
a. what is the heat change of hot water qhw?
b. what is the heat change of the cold water qcw?
assume the density of water is 1.00 G ML and specific heat of water is 4.184 j/g K
Tocale st" the calori neler eup you finst Put 46 mL ofcald wat rinthe e Rand m ensure its temperature to be 21.7%. You then po r50mLofhat weer Oemp interpreting the oooling curve below. the final temperature affer miaing is 30.4 tre 50.1 C into PART A COOLING CURVE DETERMINATION OF THE HEAT CAPACITTY OF THE CUP CALORIMETER 40 35 30- 25 20 6co 200 me (s as s 3s 67 (01505 VC3Explanation / Answer
a)
heat chang efor water:
Q = m*C*(Tf-Ti)
Cwater = 4.184 J/gC
assume D= 1 G/mL so 59 mL = 59 g
Q = 59*4.184*(39.4-50.1) = -2641.35 J, i.. it loses energy
b)
Qcold = m*C*(Tf-TI)
Qcold = 45*4.184*(39.4-21.7) = 3332.556 J gained
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