MULTIPLE CHOICE. Choose the one alternative that best completes the question. 1)
ID: 557445 • Letter: M
Question
MULTIPLE CHOICE. Choose the one alternative that best completes the question. 1)In which of the following aqueous solutions would you expect Cul to have the highest solubility? 1) A) 0.038 M Nal B) 0.025 M Lil C) 0.0125 MK D) 0.050 M CuNO3 E) Cul will have the same solubility in all solutions 2)Calculate the pOH of a 0.0727 M aqueous sodium cyanide solution at 25.0Kb for CN-is 2) 49 10-10 A) 10.00 B) 9.33 C 1.14 D) 5.22 E) 8.78 3) In basic solution, C)[H30.1-0M D) [OH-]>7.00 4) How many milliliters of 0.120 M NaOH are required to titrate 50.0 mL of to the equivalence point? The Kg of hydrazoic acid is 1.9 B) 4.80 105 A) 500 C) 60.1 D) 4.54 E) 41.6 5)The Kaofhydrazoic acid (HN3) is 1.9 x 10-5 at 25.0What is the pH of a 0.30 M aqueous 5) solution of HN3? A) 0.52 B) 5.23 C) 2.10 D) 262 E)-3.46 6) What is the pOH of an aqueous solution at 25.0 °C in which [H*] is 0.0030 M2 6) A) 8.19 B)-8.19 C)-11.48 D) 11.48 E) none of the above C-1Explanation / Answer
1)
Solubility equilibrium of CuI is,
CuI(s) <--------> Cu+(aq) + I- (aq)
According to Le Chatelier principle, as increasing the concentration of reacts of a equilibrium system, the equilibrium shifts toward products. As increasing the concentration of products of a equilibrium system, the equilibrium shifts toward the reactants.
So, increasing the concentration of Cu+ or I- , the solubility equilibrium shifts toward CuI(s). So, the solubility decreases.
Addition of NaI or LiI, or KI will produce one of the product I-. So, the solubility decreases. Also addition of CuNO3 produces one of the reactant Cu+, so the solubility decreases.
The solubility of CuI will be higher in solution that produce fewer amount of product.
Since 0.0125 M KI produce fewer amount of I- (0.0125 M), the solubility of CuI is highest in this solution.
Answer: C
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.