4 Chem 1211 Section 14 Form A 1. Which of the following types of electromagnetic

Question

4 Chem 1211 Section 14 Form A 1. Which of the following types of electromagnetic radiation has the shortest wavelength? a. Infrared light b. Gamma rays c. Purple light d. Radio waves e. Blue light Calculate the wavelength in nm of yellow light from burning sodium if the frequency is 5.09 10s. 2. a. 211 nm b. 456 nm c. 589 nm d. 900. nm e. 9.00 10-7nm 3. Higher frequency light waves are: a. Brighter than lower frequency light waves b. Dimmer than lower frequency light waves c. Not brighter or dimmer based on frequency d. Definitely lower in amplitude than lower frequency light waves e. Definitely higher in amplitude than lower frequency light waves 4. If 4 what are the possible values for !? a. 0, 1 b. 1, 2, 3, 4 d. 0, 1, 2, 3 e. 0, 1, 2, 3, 4

Explanation / Answer

increase order of energy values.
gamma rays>x-rays>UV>visible>IR>microwaves>ratio waves> T.V waves
The energy is more wave legth is less.
gamma rays have shortest wave length.
b. Gamma rays.
2. C = v* lamda
   lamda = C/V
           = 3*10^8/5.09*10^14 = 589*10^-9m = 589nm
3.b
4.n=4 l values are 0 to (n-1)
n= 4   l= 0,1,2,3
d. 0,1,2,3

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