Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+02(g

Question

Sulfur dioxide and oxygen react to form sulfur trioxide, like this: 2SO2(g)+02(g)--2503(g) Suppose a mixture of SO,, O2 and SO, has come to equilibrium in a closed reaction vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left. perturbation change in composition shif i equilibrium to the right The pressure of so2 will? to the left Some So is removed. The pressure of Op will? O (none) to the right The pressure of O2 will? The pressure of SOs wil? O to the left (none) O to the right Some SO2 is added. The volume of the vessel is reduced to the left The pressure of so will ? (none)

Explanation / Answer

1)

Removing product will shift the reaction in the direction of product as per Le chatelier Principle

So, Equilibrium moves to product side

Answer:

The pressure of SO2 will decrease

The pressure of O2 will decrease

to the right

2)

Adding reactant will shift the reaction in the direction of product as per Le chatelier Principle

So, Equilibrium moves to product side

Answer:

The pressure of O2 will decrease

The pressure of SO3 will increase

to the right

3)

Decreasing volume will increase the pressure which in turn shift the reaction in a direction which have lesser gaseous molecules as per Le chatelier Principle

Here product has less gaseous molecule

So equilibrium will move to right

So, Equilibrium moves to product side

Answer:

The pressure of SO3 will increase

to the right

  

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