Sulfur dioxide gas (SO2 (g)) can react with the oxygen gas (O2 (g)) in air to cr

Question

Sulfur dioxide gas (SO2 (g)) can react with the oxygen gas (O2 (g)) in air to create sulfur trioxide gas (SO3 (g)). Find the equilibrium ratio of sulfur trioxide to sulfur dioxide gas at standard conditions in air at 25C and 1 atm. You can assume that air is 20% oxygen and 80% nitrogen gas by volume. (B) SO3 (g) can further react with water vapor to form sulfuric acid, H2SO4 (g). Air that is in equilibrium with liquid water at 25C has a partial pressure of H2O (g) of 0.05 atm. Find the equilibrium ratio of partial pressures of H2SO4 (g) to SO3 (g) in air at 25C.

Explanation / Answer

2 SO2 + O2 = 2 SO3 , K = [SO3]^2 / [ SO2]^2 *[O2] where,K is the equilibrium constant and square brackets denote concentration since, we are dealing with gas concentration can be replaced by partial pressure hence,

[SO3]/[SO2] = (K * [O2]) ^(2)

SO3 + H2O = H2SO4 ,given partial pressure of H2O = 0.05 atm

K = P (H2SO4) / P(SO3)* P (H2O) where, P denotes the partial pressure .

P(H2SO4) / P (SO3) = K * 0.05

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