Which reactant is in excess and how many grams of the reactant will remain after

Question

Which reactant is in excess and how many grams of the reactant will remain after the reaction is complete?

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced CaCO,(s) +2HCl(aq) Caci,(aq) + H,O(r) + CO2(g) How many grams of calcium chloride will be produced when 27.0 g of calcium carbonate are combined with 12.0 g of hydrochloric acid? Number 18.3 g CaCI, Which reactant is in excess and how many grams of this reactant will remain after the reaction is complete? Number CaCO3 14.4 g of O Hc Incorrect The molar mass of CaCO is approximately 100 g/mol. Thus, the mass of CaCO3 that reacts is 100x 2(the number of moles of HCI). Subtract the amount of CaCOs that reacts from the amount initially present.

Explanation / Answer

CaCO3 is in excess

Moles of CaCO3 = 27 ÷ 100= 0.27 moles

Moles of HCl = 12 ÷ 36.5 = 0.32 moles

Here ,

2 mole of HCl is requried for 1 mol of CaCo3

So, 0.32 will react with = 0.32 ÷ 2 moles of CaCO3 = 0.16 moles

So the remaining moles of CaCO3 = 0.27 - 0.16 = 0.11

In grams = molar mass × moles

= 100 × 0.11 = 11 grams

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