2 attempts let Check my work Repo Be sure to answer all parts. Calcium dibhydrog

Question

2 attempts let Check my work Repo Be sure to answer all parts. Calcium dibhydrogen phosphate, Ca(H,PO, and sodium hydrogen carbonate, NaHCO, are to rise: Guide ingredients of baking powder that react with each other to produce CO, which causes dough or batter (unbalanced] Ca(H,PO6+NaHco,)CO) Ho) CaHPO()+Na,HPO,(s) If the baking powder contains 31.0% NaHCO3 and 35.0% Ca(H2PO4)2 by mass: (a) How many moles of CO, are produced from 8.06 g of baking powder? mol CO (b) If I mol of Co, occupies 37.0 L at 350°F (a typical baking temperature), what volume of CO2 is produced from 8.06 g of baking powder?

Explanation / Answer

Ca(H2Po4)2(S) + 2NaHcO3(s) ----> 2CO2(g) + 2H2O(g) + CaHPO4(s) + Na2HPo4(S)

1 mol Ca(H2Po4)2 = 2 mol NaHCO3

mass of Ca(H2Po4)2 = 35 g

no of mol of Ca(H2Po4)2 = w/mwt = (8.06*35/100)/234.05 = 0.012 mol

no of mol of NaHCO3 = w/mwt = (8.06*31/100)/84 = 0.0297 mol

limiting reactant = Ca(H2Po4)2

a) no of mol of CO2 produced = 0.012*2/1 = 0.024 mol

b) n1/v1 = n2/v2

   (1/37) = (0.024/v2)

V2 = 0.888 L

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