1.Ammonia, NH3(g), reacts with oxygen, O2 (g), to form nitrogen dioxide, NO2(g),
ID: 545791 • Letter: 1
Question
1.Ammonia, NH3(g), reacts with oxygen, O2 (g), to form nitrogen dioxide, NO2(g), and water, H2O(g), according to the following equation. 4NH3(g) + 7O2(g) 4NO2(g) + 6H2O(g) You react ammonia, and oxygen,and at the end of the experiment you find that you produced 27.0 g of water, and have some ammonia left over. Determine the mass of oxygen reacted. Please show all of your work for credit.
2.Reacting 3.00 mol nitrogen gas with 6.00 mol of hydrogen gas will produce how many moles of ammonia according to the following balanced chemical equation?
N2(g) + 3H2(g) ® 2NH3(g)
Explanation / Answer
1)
Molar mass of H2O,
MM = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
mass of H2O = 27 g
molar mass of H2O = 18.016 g/mol
mol of H2O = (mass)/(molar mass)
= 27/18.016
= 1.4987 mol
According to balanced equation
mol of O2 required = (7/6)* moles of H2O
= (7/6)*1.4987
= 1.7484 mol
mass of O2 = number of mol * molar mass
= 1.7484*32
= 56.0 g
Answer: 56.0 g
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