View saved SafeSearch Practices for Chapter 16 LOs-win a. Design Layout Referenc

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View saved SafeSearch Practices for Chapter 16 LOs-win a. Design Layout References Mailings Review View 120 .IA-A- A- :-:,1-.--. !it M nes New Ro .abe x2 x E) These aren't acids and bases. A) HPO- C) H E) None of tx strong acids of S. Diferentiate momoprotc, diprotic and riprotic ecids 0.375 g of a monoprotis acid (molar mass is 245 jgme) is dissolved in water to mL of a solution with plt-3.28. What is the value of K of the acid? A) 8. 6 x 103 B)4.5 x 104 C)7.4 x 10 produoe 25 2011 Words English (US) Air 1

Explanation / Answer

Let the monoprotic acid be HA

moles of HA = mass/molar mass = 0.375g/245g/mol = 0.0015moles

[HA] = 0.0015moles/0.025L = 0.06M

pH = 3.28

pH = -log[H+]

[H+] = 10-3.28 = 5.25*10-4 M

HA + H2O <---> A- + H3O+

Ka = [A-][H3O+]/[HA]

Ka = (5.25*10-4)(5.25*10-4) / (0.06)

Ka = 4.5*10-6

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