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View History Bookmarks Window Help newconnect.mheducation.com Saved ents of Matter 3 attempts left Check my work Be sure to answer all parts. Fluoride ion is poisonous in relatively low amounts: 0.2 g of F per 70 kg of body weight can cause death. Nevertheless, in order to prevent tooth decay, F ions are added to drinking water at a concentration of I mg of F" ion per L of water How many liters of fluoridated drinking water would a 70-kg person have to consume in one day to reach this toxic level? How many kilograms of sodium fluoride would be needed to treat a 7.16 x 107-gal reservoir? ×10 kg NaF 10

Explanation / Answer

Q 1mg= 10-3g

N×10-3=0.2 g

N= 200 litre

Q total no of litres = 3.78×7.16×107

24.9×107

M× 10-3=24.9×107

M=24.9×1010g

M=24.9×1010/103=24.9×1013 kg

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