For the reaction, shown below, determine which statements are True and which are

Question

For the reaction, shown below, determine which statements are True and which are False 3Fe(s) + Cr2Oy2"(aq) + 14H +(aq) 3Fe2+(aq) + 2Cr3"(aq) + 7H20(1) -1.77V FalseThe oxidation state of chromium in dichromate is +3. True The oxidizing agent is Cr3+ (aq) FalseThe chromium half-reaction takes place in an acidic solution. True The reducing agent is Fe2+ (aq) TrueThe oxidation state of hydrogen changes from +1 to 0 FalseThe highest oxidation state for chromium in this reaction is +7 If necessary, separate this into two half reactions to determine the oxidizing and reducing agents. Oxidation states can be calculated by remembering that oxygen usually has an oxidation state of 2-, except in O-O or 0-0 bonds. Hydrogen usually has an oxidation state of 1+, except in H2 12. Submit Answer You have entered that answer before Incorrect. Tries 8/45 Previous Tries

Explanation / Answer

1)

Oxidation state of Cr in Cr2O72- is +6

So, option 1 is false

2)

oxidising reagent is reactant

So, option 2 is false

3)

Oxidation state of Cr in Cr2O72- is +6

This is correct as there is H+ in redox reaction

So, option 3 is true

4)

reducing reagent should be reactant

So, option 4 is false

5)

oxidation state of hydrogen is +1 on both sides

So, option 5 is true

6)

Oxidation state of Cr in Cr2O72- is +6

This is highest oxidation state of Cr

So, option 6 is false

Answer:

false

false

true

false

true

false

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