1. To what Celsius temperature must 67.5 mL of krypton gas at 17.0°C be changed
ID: 540515 • Letter: 1
Question
1. To what Celsius temperature must 67.5 mL of krypton gas at 17.0°C be changed so the volume will triple? Assume the pressure and the amount of gas are held constant. Enter your answer to four significant figures.
2. Calculate the volume of 50.5 g of C2H2 gas at standard temperature and pressure (STP). Use a molar mass with at least as many significant figures as the data given.
3. Calculate the volume of 41.5 g of NH3 gas at standard temperature and pressure (STP). Use a molar mass with at least as many significant figures as the data given.
Explanation / Answer
1)
Given:
Ti = 17.0 oC
= (17.0+273) K
= 290 K
Vi = 67.5 mL
Vf = 3*Vi = 3*67.5 = 202.5 mL
use:
Vi/Ti = Vf/Tf
67.5 mL / 290.0 K = 202.5 mL / Tf
Tf = 870 K
Tf = 597 oC
Answer: 597 oC
2)
Molar mass of C2H2,
MM = 2*MM(C) + 2*MM(H)
= 2*12.01 + 2*1.008
= 26.036 g/mol
mass(C2H2)= 6.8 g
number of mol of C2H2,
n = mass of C2H2/molar mass of C2H2
=(6.8 g)/(26.036 g/mol)
= 0.2612 mol
Given:
P = 1.0 atm
n = 0.2612 mol
T = 273.0 K
use:
P * V = n*R*T
1 atm * V = 0.2612 mol* 0.0821 atm.L/mol.K * 273 K
V = 5.85 L
Answer: 5.85 L
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