Analysis of a Carbonated Beverage Here is the data please complete the rest of b

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Analysis of a Carbonated Beverage

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a Carbonated Beverage Form Repu is ATA Name of Beverage: f sampl pH after de-gassing: of samp on stock NaoH solution on of prepara Concentra 2 volume stock NaoH solution used: of Mass of KHP calculated to neutralize 15 mL of 0.04 M NaoH 0.17 Solution Standardization Trial 2 Trial 1 Phthalate 40 mL. Final volume NaOH mL. Initial volume NaOH Vol. NaOH consumed l5.40 mL. Determination of Citric Acid Trial 2 Trial 1 Citric acid Final volume NaOH wo. mL Initial volume NaoH o o 2 mL. Vol. NaOH consumed 10.83 mL Determination of Beverage Sample Trial 1 Trial 2 mL Beverage 30.3 mL 20.00 ml. Final volume NaOH 3.42 mL Initial volume NaOH o op m Vol. NaOH consumed 3 42 mL

Explanation / Answer

The Pproposed reaction equation between acetic acid and NaOH is as follows

C3H5O(COOH)3 + 3 NaOH ->  Na3C3H5O(COO)3 + 3 H2O

so 3 mole NaOH use one mole citric acid

moles of citric acid trial 1 = 7.3*140-5 moles

moles of citric acid trial 2 = 7.8*10-5 moles

No of moles NaOH required per mole citric acid = 3

No of moles citric acid required per mole NaOH = 1/3

From equation it is evident that there are 3 acidic hydrogen atoms per molecule of citric acid.

From equation it is evident that there are 1/3 citric acid molecule atoms per molecule of acidic hydrogen.

For the beverage sample

moles of NaOH consumed in trial 1 = 3.42 * 2.75 *10-2 = 9.4 * 10-2 moles

trial 2 = 3.2 * 2.75 *10-2 = 8.8*10-2 moles

moles of citric acid nuetralized trial 1= 9.4 * 10-2 / 3 = 3.1 * 10-2 moles

trial 2 = 8.8*10-2/3 = 2.933 *10-2 moles

For calculation of later parts Volume must be mentioned for citric acid and beverage are required

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