Analysis of a Carbonated Beverage DATA Beverage Sample Volume of sample aa mL Na

Question

Analysis of a Carbonated Beverage DATA Beverage Sample Volume of sample aa mL Name of Beverage: a Initial pH of sample pH after de-gassing s Solution Preparation Concentration of stock NaOH solutio volume of stock NaOH solution used Mass of KHP calculated to neutralize 15 mL of 0.04 M NaoH: g Solution Standardization Trial 1 Trial 2 Phthalate Final volume NaOH mL Initial volume NaOH au mL Vol. NaoH consumed haa ml. mL, Determination of Citric Acid Trial 1 Trial 2 Citric acid Final volume NaOH z. mL. Initial volume NaOH mL. mL. Vol. NaOH consumed ml Determination of Beverage Sample Trial 1 Trial 2 Beverage Final volume NaOH Initial volume NaOH u mL Vol. NaOH consumed mL. mL

Explanation / Answer

H3C6H5O7(aq) + 3NaOH(aq) ======> 3H2O(l) + Na3C6H5O7(aq)

Trial 1:

Moles of citric acid = amount of citric acid / molar mass

= 0.04 g/ 192.124 g/mol

=2.1*10^-4 moles

NaOH Concentration = 0.0425 M

Volume of NaOH:

14.8 ml or 0.0148 L

Molarity = number of moles / volume in L

Number of moles = volume in L * Molarity

= 0.0148 L *0.0425 M or moles /L

= 6.29*10^-4 moles NaOH

Trial 2:

Moles of citric acid = amount of citric acid / molar mass

= 0.04 g/ 192.124 g/mol

=2.1*10^-4 moles

NaOH Concentration = 0.0425 M

Volume of NaOH:

13.05 ml or 0.01305 L

Molarity = number of moles / volume in L

Number of moles = volume in L * Molarity

= 0.01305 L *0.0425 M or moles /L

= 5.55*10^-4 moles NaOH

H3C6H5O7(aq) + 3NaOH(aq) ======> 3H2O(l) + Na3C6H5O7(aq)

From the reaction number of moles of NaOH per mole of citric acid = 3

number of moles of citric acid per mole of NaOH = 1/3

The equation between citric acid and NaOH are as follows:

H3C6H5O7(aq) + 3NaOH(aq) ======> 3H2O(l) + Na3C6H5O7(aq)

There are three acidic hydrogen per molecule of citric acid.

Number of citic acid per acidic hydrogen atom = 1/3

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