PLEASE ANSWER B-E IN THE PICTURE USING THE TABLES The technician also collected
ID: 535919 • Letter: P
Question
PLEASE ANSWER B-E IN THE PICTURE USING THE TABLES
The technician also collected absorbance readings for the 5 over-the-counter drugs for review. The data collected for the 5 over the counter drugs is shown in Table 3. B. Create a Beer's law plot and best fit line for the data in Table 2. C. Use the Beer's law plot and best fit line to determine the concentrations for samples: M21050- 1, M21050-2, M21050-3, M21050-4, M21050-5. D. The company reported that sample M21050-2 has an M concentration of 0.0003M. Assuming that the results in Question C are 100% accurate and without error, is the company's statement accurate? What is the percent error between the reported concentration and the concentration calculated in Question C? E. By law, Drug Company Q must have an M concentration between 2.85 times 10^-4 M and 3.15 times 10^-4 M. Do all samples analyzed meet the legal requirements? Use the information from Question C to explain your answer.Explanation / Answer
Absorbance = 2 - log(%T)
From the above data,
B. Calibration curve,
Solution 1, Absorbance = 2 - log(17.9) = 0.747
Solution 2, Absorbance = 2 - log(25) = 0.602
Solution 3, Absorbance = 2 - log(35.7) = 0.447
Solution 4, Absorbance = 2 - log(50.2) = 0.300
Solution 5, Absorbance = 2 - log(70.8) = 0.150
Plot concentration on x-axis and absorbance on y-axis
slope = molar absorptivity
= (0.150 - 0.300)/(8 x 10^-5 - 1.6 x 10^-4)
= 1875 M-1.cm-1
C. Concentration = absorbance/molar absorptivity
concentration in,
M21050-1 = [2-log(44.1)]/1875 = 1.896 x 10^-4 M
M21050-2 = [2-log(45.8)]/1875 = 1.809 x 10^-4 M
M21050-3 = [2-log(42.1)]/1875 = 2.00 x 10^-4 M
M21050-4 = [2-log(30.1)]/1875 = 2.781 x 10^-4 M
D. No the result given by company is incorrect. It is lower than the value reported.
%error = (0.0003 - 0.0001809) x 100/0.0003 = 39.70%
E. No the values for some turned out to be lower than the needed value. So it is below the legal limit.
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