Part C When you are presented with additional details, it can sometimes be a lit

Question

Part C

When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution map and dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value. The following dimensional analysis setup could be used to determine the theoretical mass of AlBr3(s) (molecular mass = 266.69 g/mol ) produced based on reacting 40.7 g of a 0.060 mol/L solution of Br2(l) (density = 1043 g/L ) with excess Al(s) as described in the following equation: 3Br2(l) + 2Al(s) 2AlBr3(s) Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or denominator when calculating the mass of AlBr3(s) produced from a sample of Br2(l). Drag the appropriate values to their respective targets.

Explanation / Answer

The reaction taking place is:

3Br2(l) + 2Al(s) 2AlBr3(s)

Volume of bromine solution taken = Mass taken/Density = 40.7/1043 = 0.039 L

So, moles of Br2 taken = Molarity*Volume = 0.060*0.039 = 0.00234 moles

According to reaction stoichiometry, moles of AlBr3 produced = (2/3)*0.00234 = 0.00156 moles

Mass produced = moles*MW = 0.00156*266.69 = 0.416 grams

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