I am most looking for help in the part b of the question. I have written down th

Question

I am most looking for help in the part b of the question. I have written down the dissociation equations for HCl and CH3COOH and found that both contribute a hydronium ion to the equilibrium. I also calculated the concentration of each but I am not sure it is correct. Thank you for any help that can be provided. Question B1 Solid calcium carbonate can dissolve in carbonated water to form both hydrated calcium and bicarbonate ions according to the following equation: Cacoa (s) coz (aq) H20() Caz (aq) 2HCO3 (aq) (a) Write the expression for the equilibrium constant, Kc, for this reaction: (1 mark) (b) Bicarbonate ions also participate in the following equilibrium: Consider the following two separate experiments and circle the system that will result in the greatest volume of CO2 gas at equilibrium Experiment 1: 50 mL of 0.5 M HCI is added to the above equilibrium mixture. equilibrium 2: 50 mL of 0.5 M CH,cooH (Ka 1.8 x 10 6) is added to the above mixture. Experiment 1 or Experiment 2 or Neither (circle one option) Explain this observation.

Explanation / Answer

HCL BEING a strong acid is completely dissociated while acetic acid is weak acid and partially dissociated. Hence hcl give large conventration of h+ ions as compared to ch3cooh. Applying le chatliers principle increase in concentraion of h+ ion push the reaction to the left side and yield large amount of co2. That is why concentration of co2 will be large when hcl is added.

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