An n-butane (n-C_4H_10) is isomerized to i-butane (i-C_4H_10). A gas reacto has

Question

An n-butane (n-C_4H_10) is isomerized to i-butane (i-C_4H_10). A gas reacto has a feed of a molar flowrate of 300 mole/h at 200 degree C. The feed composition is 80 mole% n-butane, 15 mole% i-C_4H_10 and the balance is HCI. The conversion of n-butane is 60% and the product is at 240 degree C. Calculate the required rate of heat input or output from the reactor in kJ/s. The operating pressure kept constant at 1.0 atm. conversion reaction type in Simulation Basis Manager and once in simulation environment use Conversion reactor.

Explanation / Answer

Moles of n- butane =80% * 1mole

=0.8 moles

Change in temperature = 240- 200

= 40 degree Celsius

Molar mass of the n- butane = 58 g/mole

Given weight of the n- butane is = 0.8 × 58

= 46.4 g

0.0464kg

U= m c T

U= 0.0464 kg×4.184 J/ kgC × 40

U= 7.76k J

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