An isotope with Z > 83, which lies close to the band of stability, will generall

Question

An isotope with Z > 83, which lies close to the band of stability, will generally decay through __________________________. a. positron decay b. ? decay c. ? decay d. ? decay e. electron capture

Explanation / Answer

a) Nuclides with Z > 83 decay through a decay. b) The N/Z ratio for Cr-48 is (48 - 24)/24 = 1.00. This number is below the band of stability because N is too low and Z is too high. To become more stable, the nucleus decays by converting a proton to a neutron, which is positron decay. Alternatively, a nucleus can capture an electron and convert a proton into a neutron through electron capture. c) The N/Z ratio for Mn-50 is (50 - 25)/25 = 1.00. This number is also below the band of stability, so the nuclide undergoes positron decay or electron capture.

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