An n-bit register can hold 2^n distinct bit patterns. As such, it can only be us

Question

An n-bit register can hold 2^n distinct bit patterns. As such, it can only be used to address a memory whose number of addressable units (typically, bytes) is less than or equal to 2^n. In this question, register sizes need not be a power of two. K = 2^10 What is the minimum size of an address register for a computer with 5 TB of memory? answer = ________ bits What is the minimum size of an address register for a computer with 7 TBs of memory? answer = ________ bits What is the minimum size of an address register for a computer with 2.5 PBs of memory? answer = _________ bits

Explanation / Answer

we know, for 2^n bit register, we require n bit address register i.e., log2(memory).

a.) log2(5 * 2 ^40) = log2(5) + log2(2 ^40) = 3+40 = 43 bits (approx)

b.) log2(7 * 2 ^40) = log2(7) + log2(2 ^40) = 3+40 = 43 bits (approx)

c.) log2(2.5 * 2 ^50) = log2(2.5) + log2(2 ^40) = 2+50 = 52 bits (approx)

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