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Determine the value of K_c for the following reaction if the equilibrium concent

ID: 527805 • Letter: D

Question

Determine the value of K_c for the following reaction if the equilibrium concentrations are as follows: [N_2]_eq = 1.5 M, [H_2]_eq = 1.1 M, [NH_3]_eq = 0.47 M. N_2(g) + 3H_2(g) = 2NH_3(g) 0.28 0.11 9.1 3.5 0.78 Which of the following statements is true? If Q K, it means the forward reaction will proceed to form more reactants. If Q > K, it means the reaction is not at equilibrium. A solution containing CaCl_2 is mixed with a solution of Li_2SO_3 (lithium sulfite) to form a solution that is 2.1 times 10^-5 M in calcium ion and 4.75 times 10^-5 M in sulfite ion. Describe the solution. K_ap (CaSO_3) = 2.3 times 10^-9. The solution is unsaturated. The solution is saturated. A precipitate has formed. There is an equilibrium between solid CaSO_3 and dissolved ions. There is not enough information to determine. Consider the following reaction CuS(s) + O_2(g) = Cu(s) + SO_2(g) A reaction mixture initially contains 2.9 M O_2, 1kg of CuS(s) and no products. Determine the equilibrium concentration of O_2 if K_e for the reaction at this temperature is 1.5. 0.59 M 1.9 M. 1.7 M 1.2 M 2.2 M What is the conjugate base of H_2PO_4^-? H_3PO_4 PO_4^3- HPO_4^2- H_3O^+ OH^- Which of the following solutions would have the lowest pH? Assume that they are all 0.10 M in acid at 25 degree C. The acid is followed by its K_4 value. HCN, 4.9 times 10^-10 HF, 3.5 times 10^-4 HNO_2, 4.6 times 10^-4 HCHO_2, 1.8 times 10^-4 HCIO_2, 1.1 times 10^-2 Express the equilibrium constant K for the following reaction. CO(g) = CO_2(g) + C(s, graphite) [CO_2(g)][C(s)]/[CO(g)] [CO_2(g)][CO(g)]^2 [CO_2(g)][C(s)]/[CO(g)]^2 [CO(g)]^2/[CO_2(g)] [CO_2(g)]/[CO(g)] Which of following substances are neutral when dissolved in water? NaNO_3 Fe(NO_3)_3 NH_4Br K_3PO_4 HClO_2

Explanation / Answer

Question 22

The reaction is:

N2 + 3H2 = 2NH3

The Kc equilibrium expression would be:

Kc = (NH3)2 / (H2)3(N2)

We substitute the values we get in the problem:

Kc = (0.47M)2 / (1.1M)3(1.5M)

Kc = 0.11M-2

So, the correct answer is B) 0.11.

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