Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

How many pi electrons are present in the molecule below: A) 8 B) 10 C) 12 D) 14

ID: 524854 • Letter: H

Question

How many pi electrons are present in the molecule below: A) 8 B) 10 C) 12 D) 14 The first step of electrophilic aromatic substitution reactions loads to an arenium ion intermediate. Which of the following statements is NOT true about the above intermediate? A) It is aromatic B) It is positively charged C) It has four pi electrons D) It has five sp^2 hybridized carbon atoms For nitration of nitrobenzene the predominant product is: A) o-dinitrobenzene B) P-dinitrobenzene C) m- dinitrobenzene D) 1, 4-dinitrobenzene In the Friedel-Craft's acytation reaction the electrophile is which of the following? A) nitronium cation B) acytium cation C) sulfonium cation D) alkyl cation Which reagents sequence can be used to prepare m-chloronitrobenzene? A) benzene, Cl_2/FeCl_3; HNO_3/H_2SO_4 B) benzene, HNO_3/H_2SO_4; then Cl_2/Fecl_3 C) benzene, AlCl_3; then HNO_3/H_2SO_4 D) Benzene, HNO_3; then Cl_2/FeCl_3 Which statement is NOT true about nucleophilic aromatic substitution reaction? A) The first step is addition of nucleophile to the C-atom bonded to a leaving group B) The second step is the elimination of the leaving group C) The intermediate Meisenheimer complex is positively charged D) The reaction is accelerated by powerful electron-withdrawing groups ortho the leaving group. Which of the following compounds is the strongest carboxylic acid derivative? Which of the following is a component of ant sting? A_CH_3COOH B) CH_3COCH_3 C) HCOOH D) CH_3C

Explanation / Answer

1) C . 12 electrons because 6pi bonds are there.

2) A . It is not a aromatic

3) C.meta dinitrobenzene because NO2 is withdawing group

4) B.acylium cation

5) B .First nitration followed by chlorination.

7) D.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote