The overall reaction for the lead storage battery is as follows: Pb(s) + PbO_2(s

Question

The overall reaction for the lead storage battery is as follows: Pb(s) + PbO_2(s) + 4H^+ (aq) + 2SO^2-_4 (aq) rightarrow 2PbSO_4(s) + 2H_2O(l) When the battery discharges, which of the following statements is true? A) Pb is formed at the anode. B) The pH decreases. C) PbO_2 is reduced at the anode. D) SO^2-_4 is the reducing agent. E) PbO_2 is the oxidizing agent. A strip of iron is placed in a 1 M solution of iron(II) sulfate, and a strip of copper is placed in a 1 M solution of copper(II) chloride. The two solutions are connected with a salt bridge, and the two metals are connected by a wire. Reduction Half Reaction E degree (V) Fe^2+ (aq) + 2e^- rightarrow Fe(s) -0.41 Cu^2+ (aq) + 2e^- rightarrow Cu(s) 0.34 Which of the following takes place? A) The Fe(II) concentration of the iron half-cell decreases. B) Chlorine is produced at the iron electrode. C) Chlorine is produced at the copper electrode. D) Copper atoms deposit at the cathode. E) Sulfur deposits at the iron electrode.

Explanation / Answer

27. in the reaction Pb(s) + PbO2(s) + 2H2SO4(aq) =2PbSO4(s) + 2H2O(l)

the option C is correct because the oxidation number of lead decreases from +4 in PbO2 to +2 in PbSO4, hence this is reduction and PbO2 at the anode.

28. in the reaction mentioned in the question, the galvanic cell would be formed with iron in iron sulfate as anode and copper in copper chloride as cathode.

since reduction takes place at anode, hence copper ions from the solution of copper chloride will be deposited as copper at the cathode so the correct option is D.

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