The outstretched hands and arms of a figure skater preparing for aspin can be co

Question

The outstretched hands and arms of a figure skater preparing for aspin can be considered a slender rod pivoting about an axis throughits center. (See the figure below .) When the skater's hands andarms are brought in and wrapped around his body to execute thespin, the hands and arms can be considered a thin-walled hollowcylinder. His hands and arms have a combined mass of8.50 rev/s, what is his finalangular speed? w= rev/s kg.m^2 If the skater's original angular speed is0.350 cm. The moment of inertia about the axis of rotation of the remainderof his body is constant and equal to 0.450 ; when wrapped, they form acylinder of radius 25.0 kg. When outstretched, theyspan 1.80

Explanation / Answer

I1HA = M L2 / 12    initial moment of inertia of hands & arms I1HA = 8.5 * 1.82 / 12 = 2.30kg-m2 I1 = .45 + 2.30 = 2.75kg-m2    total angular momentum ofskater I2HA = M R2 = 8.5 * .252 =.53 kg-m2 I2 = .45 + .53 = .98 kg-m2 I1 1 = I22       conservationof angular momentum 2 = 2.75 * .35 / .98 = .98 rev /sec 2 = 2.75 * .35 / .98 = .98 rev /sec

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