Balance the redox reaction in acidic solution: Fe^2+ + MnO_4^- rightarrow Fe^3+

Question

Balance the redox reaction in acidic solution: Fe^2+ + MnO_4^- rightarrow Fe^3+ + Mn^2+ 1. Separate the equation into two half-reactions 2. Balance the atoms other than O and H in each half-reaction 3. Add H_2 O to balance O atoms and H^+ to balance H atoms 4. Add electrons to one side of each half-reaction to balance the charges 5. If necessary, equalize the number of electrons in the two half-reactions by multiplying the half-reactions by appropriate coefficients 6. Add the two half-reactions together and balance the final equation by inspection.

Explanation / Answer

1) MnO4- ---> Mn2+

Fe2+   ---> Fe3+

2)   MnO4^- ---> Mn2+

Fe2+ ----> Fe3+

3) MnO4^- +      8H+ (aq) -----> Mn2+ (aq) +   4H2O (l)

Fe2+ ---> Fe3+

4)   MnO4^- (aq) + 8H+ (aq) + 5e- (aq) ---> Mn2+ (aq) + 4H2O (l)

Fe2+ (aq) ---> Fe3+ (aq) + e- (aq)

5) MnO4^- (aq) + 8H+ (aq) + 5e- (aq) ---> Mn2+ (aq) + 4H2O (l)

5Fe2+ (aq) ----> 5Fe3+ (aq) + 5e- (aq)

6) 5Fe^2+ (aq) + MnO4^- (aq) + 8H+ (aq) ---> Mn^2+ (aq) + 5Fe^3+ (aq) + 4H2O (l)

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