Balance the redox reaction in acidic solution: SO_3^2- + Fe^3+ rightarrow Fe^2+
ID: 1049917 • Letter: B
Question
Balance the redox reaction in acidic solution: SO_3^2- + Fe^3+ rightarrow Fe^2+ + SO_4^2- Separate the equation into two half-reactions Balance the atoms other than O and H in each half-reaction Add H_2O to balance O atom and H to balance H atoms Add electrons to one side of each half-reaction to balance the charge If necessary, equalize the number of electrons in the two half reactions by multiplying the half-reactions by appropriate coefficients Add the two half-reactions together and balance the final equation by inspection. Balance the redox reaction in acidic solution: CN^-+ mnO_4 rightarrow CNO^-+ mnO_2 Separate the equation into two half-reactions Balance the atoms other than O and H in each half-reaction Add H_2O to balance O atoms and H to balance H atoms Add electrons to one side of each half-reaction to balance the charges If necessary, equalize the number of electrons in the two half reactions by multiplying the half-reactions by appropriate coefficients Add the two half-reactions together and balance the final equation by inspection.Explanation / Answer
Q!.
SO3-2 + Fe+3 --> Fe+2 + SO4-2
half reactions
Fe+3 --> Fe+2
SO3-2 --< SO4-2
balance all other than O and H
Fe+3 --> Fe+2
SO3-2 --< SO4-2
balance O by adding H2O
Fe+3 --> Fe+2
H2O + SO3-2 --< SO4-2
balance H form H+
Fe+3 --> Fe+2
H2O + SO3-2 --< SO4-2 + 2H+
add electrons
e- + Fe+3 --> Fe+2
H2O + SO3-2 --< SO4-2 + 2H+ + 2e-
balance eletrcons
2e- + 2Fe+3 --> 2Fe+2
H2O + SO3-2 --> SO4-2 + 2H+ + 2e-
add half reactions
2e- + 2Fe+3 + H2O + SO3-2 --> 2Fe+2 + SO4-2 + 2H+ + 2e-
cancel common terms
2Fe+3 + H2O + SO3-2 --> 2Fe+2 + SO4-2 + 2H+
add OH-
2OH- + 2Fe+3 + H2O + SO3-2 --> 2Fe+2 + SO4-2 + 2H+ + 2OH-
2OH- + 2Fe+3 + H2O + SO3-2 --> 2Fe+2 + SO4-2 + 2H2O
2OH- + 2Fe+3 + SO3-2 --> 2Fe+2 + SO4-2 + H2O
Q2.
CN-+ MnO4- --> CNO- + MnO2
CN- --> CNO-
MnO4- --> MnO2
then
H2O + CN- --> CNO-
MnO4- --> MnO2 + 2H2O
balance H
H2O + CN- --> CNO- + 2H+
4H+ + MnO4- --> MnO2 + 2H2O
balance charges
H2O + CN- --> CNO- + 2H+ + 2e-
3e- + 4H+ + MnO4- --> MnO2 + 2H2O
balance e-
3H2O + 3CN- --> 3CNO- + 6H+ + 6e-
6e- + 8H+ + 2MnO4- --> 2MnO2 + 4H2O
add all
3H2O + 3CN- + 6e- + 8H+ + 2MnO4- --> 3CNO- + 6H+ + 6e- + 2MnO2 + 4H2O
cancel comon terms
3CN- + 2H+ + 2MnO4- --> 3CNO- +2MnO2
add OH-
2OH- + 3CN- + 2H+ + 2MnO4- --> 3CNO- +2MnO2 + 2OH-
2H2O + 3CN- + 2MnO4- --> 3CNO- +2MnO2 + 2OH-
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.