Hello, This is a Organic Chemistry GC analysis.... I performed a fractional dist

Question

Hello, This is a Organic Chemistry GC analysis....

I performed a fractional distillation on a solution that contains two unknown alcohols, then fromed GC on the first (A) and fourth(D) samples taken from the distillation process. Here I have included GC's of the sample that has all possible alcohols in it, my original sample that before distillation containing my two alcohols, and both A and D samples. Please help me figure out the % compostion of my alcohols in both samples. I believe the way you figure this out is by first finding the corrected % areas, but I really am not sure. Please help!!!

Column B RUN a 44 1901 06 44 149 START 99 269 2.673 4.133 S 015 RUN# 44 1901 06 144 49 JAN AREAx AREA TYPE UIDTH AREA20 RT 74654 PH 011 1.164 e9 55763 solvont 024 12290864 SHB 1.195 9766 BBB 01 4 1 320 243439 SBB 011 194591 BB 017 41789 269 16061 4 PU 24 17082 2.314 72429 UB 038 spe- 673 219324 PB 034 1.59811. 1.69986 4.133 233288 PB 054 015 225008 PB 082 63953 TOTAL AREA 3724 07 MUL FACTOR 0000 00

Explanation / Answer

According to GC, Solvent RT is 1.1 (varies from 1.10 to 1.19)

Comparatively low boiling Alcohol's (LBA) RT is 1.4 (varies from 1.44 to 1.51)

Comparatively low boiling Alcohol's (HBA) RT is 2.6

Relative % of alcohols excluding solvent will be= one of the alcohol percentage/ (both alcohol percentage) x 100%

Now, % composition of 1st sample, LBA (%)= 9.1/(9.1+69.4) x100= ~11.6%

HBA (%)= 69.4/(9.1+69.4) x100= ~88.4%

Similarly

In 2nd sample of LBA (%)= 23.9/(23.9+59.1) x100= ~28.7

HBA (%)= 59.1/(23.9+59.1) x100= ~71.2%

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