Hello, Please show full steps in getting the answers for the questions to get aw
ID: 800345 • Letter: H
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Hello, Please show full steps in getting the answers for the questions to get awarded !
6,7 and 9,10 Ive already got 8 !
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The unit cells for lithium oxide and silver iodide are shown here. Show that the ratio of cations to anions in each unit cell corresponds to the ratio of cations to anions in the formula of each compound. An unknown metal is found to have a density of 7.8748 g/cm3 and to crystallize in a body. centered cubic lattice. The edge of the unit cell is found to be 0.28664 nm. Calculate the atomic mass of the metal. Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length of the unit cell and the density of platinum in g/cm3. Barium has a density of 3.59 g/cm3 and crystallizes with the body-centered cubic unit cell. Calculate the radius of a barium atom. Rank the 4 solids from lowest to highest melting point and explain the ranking: C(s, diamond), Kr(s), NaCl(s), and H2O(s).Explanation / Answer
Answer question
1)for lithium oxide
thecoordination no .of Li^+=4
the co ordination number of o^-2 is=8
therefore ratio is ratio of cations to aniopns is 2:1
for silver iodide (fcc)d
the ratio of cation to anion is 1:1
2)
density=Z* M/(N*a^3)
7.8778=2*m/(6.023*10^23*[0.28664*10^-7]^3)
M=55.87GR/MOLE
3)
FOR FAC CNTERE CUBIC
EDGE LENGTH(a)=r*2*1.414
=139*10^-10*2*1.414
=393.09*10^-10cm
density=Z* M/(N*a^3)
density=4*195/6.023*10^23*(393.09*10^-10)^3
=21.3 gr/cm3
4)
density=Z* M/(N*a^3)
3.59=2*137.34/6.023*10^23*a^3
a=2.7*10^-7 cm
r= a/2*1.414
r=9.5*10^-8cm
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