(a) A piston at 4.1 atm contains a gas that occupies a volume of 3.5 L. What pre

Question

(a) A piston at 4.1 atm contains a gas that occupies a volume of 3.5 L. What pressure would have to be placed on the piston to force the volume to adjust to 1.03 L?

(b) A piston at -47.0°C contains a gas that occupies a volume of 2.5 L. To what temperature would the gas have to be heated to increase the volume to 3.8 L at constant pressure?

(c) A piston at 7745 torr contains a gas that occupies a volume of 4.7 L. What pressure would have to be placed on the piston to force the volume to adjust to 0.38 L?

Explanation / Answer

answer

a) as per equation P1V1=P2V2 at constant temperature and pressure.

here p1=4.1

V1=3.5

P2= ?

V2=1.03

so 4.1*3.5=P2*1.03

hence P2 = 4.1*3.5/1.03

P2=13.93 atm presure required on the piston to force the volumeto 1.03 L.

b) by charles law : if you hold gas at constant pressure volume varies in direct proportion with the temperature , so as temperature goes up , so does the volume.

V= cT

V=2.5

T= - 47°celcius

hence c=2.5/-47

c = 005.

to increase the volume from 2.5L to 3.8L we require temperature as per following formula.

V=cT

3.8 = 0.05 * T

hence T=3.8/0.05

T= 76°celcius. (temperature required )

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