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(a) A driver wearing a seatbelt decelerates atthe same rate as the car itself. S

ID: 1738427 • Letter: #

Question

(a) A driver wearing a seatbelt decelerates atthe same rate as the car itself. Since modern cars have a "crumplezone" built into the front of the car, the car will decelerate overa distance of roughly 1.0 m. Find the net force acting ona 88 kg driver who is deceleratedfrom 19 m/s to rest in a distance of1.0 m.
1 kN

(b) A driver who does not wear a seatbelt continues to move forwardwith a speed of 19 m/s (due toinertia) until something solid is encountered. The driver now comesto rest in a much shorter distance -- perhaps only a centimeter.Find the net force acting on a 88 kgdriver who is decelerated from 19 m/sto rest in 1.0 cm.
2 kN
(a) A driver wearing a seatbelt decelerates atthe same rate as the car itself. Since modern cars have a "crumplezone" built into the front of the car, the car will decelerate overa distance of roughly 1.0 m. Find the net force acting ona 88 kg driver who is deceleratedfrom 19 m/s to rest in a distance of1.0 m.
1 kN

(b) A driver who does not wear a seatbelt continues to move forwardwith a speed of 19 m/s (due toinertia) until something solid is encountered. The driver now comesto rest in a much shorter distance -- perhaps only a centimeter.Find the net force acting on a 88 kgdriver who is decelerated from 19 m/sto rest in 1.0 cm.
2 kN

Explanation / Answer

  (a) Given that the mass of thediver is m = 88 kg            The initial velocity of the diver is U = 19 m/s            The final velocity of the diver is V = 0 m/s            The distance travelled is d = 1.0 m ------------------------------------------------------                 From the equation of motion                      V2 - U2 = 2ad                      a = ( V2 - U2 ) / 2d                                                             The net force on the diver is F = ma                                                             = m ( V2 - U2 )/ 2d                                                                 = ---------- N -------------------------------------------------------------------------------------------------------------    (b) Given that the mass of thediver is m = 88 kg            The initial velocity of the diver is U = 19 m/s            The final velocity of the diver is V = 0 m/s            The distance travelled is d = 1.0 cm = 0.01m ------------------------------------------------------                 From the equation of motion                      V2 - U2 = 2ad                      a = ( V2 - U2 ) / 2d                                                             The net force on the diver is F = ma                                                             = m ( V2 - U2 )/ 2d                                                                 = ---------- N                                 The initial velocity of the diver is U = 19 m/s            The final velocity of the diver is V = 0 m/s            The distance travelled is d = 1.0 cm = 0.01m ------------------------------------------------------                 From the equation of motion                      V2 - U2 = 2ad                      a = ( V2 - U2 ) / 2d                                                             The net force on the diver is F = ma                                                             = m ( V2 - U2 )/ 2d                                                                 = ---------- N