(a) A ball of clay with a mass of 40 g, traveling east at 3.0 m/s, collides with

Question

(a) A ball of clay with a mass of 40 g, traveling east at 3.0 m/s, collides with a 30 g ball of clay traveling north at 1.5 m/s, and they stick together. What are the speed and the direction (with an angle in degrees) of the resulting 70 g ball of clay? (b) A billiard ball is moving east at 3.0 m/s. A second, identical billiard ball is shot west at 1.8 m/s. The balls have a glancing collision (not a head-on collision) that deflects the second balls direction by 90 degrees and sends it north at 2.27 m/s. What are the speed and direction of the first ball after the collision?

Explanation / Answer

a) 40 x 3i + 30 x 1.5j = 70v

v = 1.71i + 0.643j m/s

|v| = 1.71^2 + 0.643^2 = 1.83 m/s

= tan-1 (0.643/1.71) = 20.61 degrees from est.

b) m x 3i - m x 1.8i = m x 2.27j + mv

v = 1.2i - 2.27j

|v| = 1.2^2 + 2.27^2 = 2.57 m/s

= tan-1 (2.27/1.2) = 62.14 degrees south of east.

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.