(a) A diverging lens of focal length 5 cm, is making an image of a 3 cm tall obj

Question

(a) A diverging lens of focal length 5 cm, is making an image of a 3 cm tall object which is 7 cm away
from the lens. Theoretically, what is the position of the image?
(b) Theoretically, what is the size of the image? Should it be erect or inverted?
(c) DRAW to scale the ray diagram, showing the object and image.
(d) REDRAW the system, now replacing the lens by a convex mirror of the same focal length [Hint, be
sure to draw the proper radius of curvature for the mirror!].
(e) Thought Question: Would it be possible to get a similar sized virtual image by using either a
converging lens or mirror? If so, what would be its focal length?

Explanation / Answer

1. for diverging lens -1/f = 1/u +1/v 1/v = 1/u +1/f v = fu/f+u = 35/2 = -17.5 cm 2.m = -(-17.5/7) = 2.5 image is erect image size Y' = 2.5 * 3 = 7.5 cm

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