Glycolysis is an anaerobic process because a. Glycolysis needs O_2; without O_2

Question

Glycolysis is an anaerobic process because a. Glycolysis needs O_2; without O_2 glycolysis will not flux. b. NAD necessary for glycolysis can be regenerated without O c. Glycolysis requires inorganic phosphate in addition to ATP. d. More than one of the above. Phosphoglucomutase (PGM) catalyzes the isomerization of 3PG rightarrow 2PG. PGM is said to have "kinase activity". This is because a. PGM catalyzes a functional group shift within the same molecule. b. When PGM is catalyzing its reaction it actually transfers a phosphate from one species to another. c. More than one answer choice is why PGM is said to have "kinase activity". d. PGM creates a substrate to that binds to Hb. If the a water molecule enters the active site during catalysis by the enzyme hexokinase, then a. ADP is formed but glucose-6-phosphate is not. b. glucose-6 phosphate acts as a competitive inhibitor. c. the reaction is unaffected. d. more than one of the above. Which of the following represents a hydride? a. H^- b. H c. H_2 d. H+ According to this graph, curve A corresponds to _____ and curve B corresponds to _____.a. glucokinase; hexokinase b. hexokinase; glucokinase c. pyruvate kinase; hexokinase d. hexokinase; pyruvate kinase The enzyme pyruvate dehydrogenase kinase a Catalyzes the transfer of a phosphate group from the enzyme pyruvate dehydrogenase to ADP. b. Catalyzes the shifting of a phosphate group in enzyme E1 of pyruvate dehydrogenase kinase. c. Catalyzes the transfer of a phosphate group from ATP to the enzyme pyruvate dehydrogenase. d. Catalyzes redox reaction where a NAD+ is reduced to NADH and a FADH_2 in active site of the pyruvate dehydrogenase kinase is oxidized.

Explanation / Answer

QUESTION 32

Anaerobic processes does not require oxygen. Thus glycolsis is an anaerobic process as NAD+ can be regenerated without oxygen.

Solution: b

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